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An airplane departs at exactly 8:08:08 a.m. and arrives at its destination at exactly 3:03:03 p.m. To the nearest second, exactly what was the plane's travel time?

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mathematics

Calculating the travel time of a journey often requires more than simple subtraction, especially when the minutes and seconds of the arrival time are less than those of the departure time. This is a common scenario in travel and highlights the importance of understanding how we measure and calculate time. The time system we use, with 60 seconds in a minute and 60 minutes in an hour, has its roots in the ancient Sumerian and Babylonian cultures. They used a sexagesimal (base-60) number system, which has been carried down through the millennia and is still fundamental to how we measure both time and angles.

To find the plane's travel time, we subtract the departure time from the arrival time, starting with the seconds, then minutes, and finally hours. First, we convert the arrival time to a 24-hour format, so 3:03:03 p.m. becomes 15:03:03. When we try to subtract the seconds (3 - 8), we have to "borrow" from the minutes. We take one minute from the '03' minutes, leaving '02', and add 60 seconds to the '03' seconds, giving us 63 seconds. Now we can subtract: 63 - 8 = 55 seconds.

Next, we subtract the minutes. Since we borrowed a minute, we now have 02 minutes for the arrival time. We can't subtract 8 minutes from 2, so we must borrow from the hours. We take one hour from the 15 hours, leaving 14, and add 60 minutes to our 2 minutes, giving us 62 minutes. Now we can subtract: 62 - 8 = 54 minutes. Finally, we subtract the hours: 14 - 8 = 6 hours. This process of borrowing across different units of time gives us the precise travel duration of 6 hours, 54 minutes, and 55 seconds.