What is be the minimum number of baseball players from both teams who could come to bat in a 9-inning baseball game which ends with the score 1-0?

This fascinating baseball puzzle combines the rules of the game with a bit of logic. To find the absolute minimum number of plate appearances, we must assume maximum efficiency in making outs. For the losing team, the task is straightforward but grim. Since they scored no runs, we can assume every batter who came to the plate made an out. A full nine-inning game requires a team to record 27 outs (3 outs per inning x 9 innings). Therefore, the losing team must have sent exactly 27 batters to the plate, with each one being retired.

The winning team's situation is more complex because they must score one run. The key to minimizing the total is for the winning team to be the home team. If the home team is leading after the top of the ninth inning, they do not bat in the bottom of the ninth, thus saving three potential batters. This means the winning team only bats for eight innings. For seven of those innings, they can be perfectly inefficient, with three batters coming up and making three outs (21 batters).

In the one inning they score, they must do so with the fewest players possible. This is achieved when the first batter hits a solo home run. After that, the next three batters must make outs to end the inning. This scoring inning requires four batters. Adding it all together, the winning home team used 25 batters (21 in their scoreless innings + 4 in their 1-run inning).

So